10x^2-32=0

Solution for 10x^2-32=0 equation:

10x^2-32=0

a = 10; b = 0; c = -32;
Δ = b2-4ac
Δ = 02-4·10·(-32)
Δ = 1280
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1280}=\sqrt{256*5}=\sqrt{256}*\sqrt{5}=16\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16\sqrt{5}}{2*10}=\frac{0-16\sqrt{5}}{20}
=-\frac{16\sqrt{5}}{20}
=-\frac{4\sqrt{5}}{5}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16\sqrt{5}}{2*10}=\frac{0+16\sqrt{5}}{20}
=\frac{16\sqrt{5}}{20}
=\frac{4\sqrt{5}}{5}
$